5-4x^2=1.2

Solution for 5-4x^2=1.2 equation:

5-4x^2=1.2

We move all terms to the left:

5-4x^2-(1.2)=0

We add all the numbers together, and all the variables

-4x^2+3.8=0

a = -4; b = 0; c = +3.8;
Δ = b2-4ac
Δ = 02-4·(-4)·3.8
Δ = 60.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{60.8}}{2*-4}=\frac{0-\sqrt{60.8}}{-8}
=-\frac{\sqrt{}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{60.8}}{2*-4}=\frac{0+\sqrt{60.8}}{-8}
=\frac{\sqrt{}}{-8}
$